Final answer:
To find the mass of ZnS precipitated, you would need to use the volume and molarity of the solution to calculate moles, then use the molar mass of ZnS (97.44 g/mol) to find the mass. However, the question lacks complete data to provide a precise answer.
Step-by-step explanation:
The question does not provide the complete information on what the 1.76 is related to (like the molarity of a solution which would be essential information to calculate the amount of ZnS precipitate). However, I can guide you on how to solve the problem if you had the concentration.
If 1.76 M is the concentration of a solution that reacts with Zn2+ ions to precipitate ZnS, you would first calculate the number of moles of reactant using the volume and molarity (M).
To find the mass of precipitated ZnS:
- Calculate moles of the reactant from volume (V) and molarity (M) using the formula:
- moles = M × V
- Use the stoichiometry from the balanced chemical reaction to find moles of ZnS precipitated.
- Calculate the mass of ZnS precipitated using the molar mass of ZnS (97.44 g/mol).
Note: To answer completely, the reaction and molarity of the other reactant are needed.