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How much water must be added to 43.0 g of BaCl₂ to produce a solution that is 35.0 percent BaCl₂ by mass?

User Ntep Vodka
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1 Answer

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Final answer:

To create a 35.0% BaCl2 by mass solution, one must add 37.7143 g of water to 43.0 g of BaCl2.

Step-by-step explanation:

To calculate how much water must be added to 43.0 g of BaCl2 to produce a solution that is 35.0 percent BaCl2 by mass, we can use the mass/mass percent formula:

mass percent = (mass of solute / mass of solution) x 100%

Here, BaCl2 is the solute, and we need to find the mass of the water (solvent) required. Given that the mass of the solute (BaCl2) is 43.0 g and the desired mass percent is 35.0%, we can set up the equation:

35.0 = (43.0 g / (43.0 g + mass of water)) x 100%

Solving for the mass of water:

mass of water = (43.0 g / 0.35) - 43.0 g = 80.7143 g - 43.0 g = 37.7143 g

Therefore, 37.7143 g of water must be added to 43.0 g of BaCl2 to achieve a 35.0% BaCl2 by mass solution.

User Riaj Ferdous
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