Final answer:
To find the mass of carbon monoxide in a 893 L container at STP, calculate the number of moles based on the volume and then multiply by the molar mass, yielding approximately 1116.69 grams.
Step-by-step explanation:
The question asks to find amount of grams which this container with a volume of 893 L of carbon monoxide contain at STP. To solve this, we apply principles from the subject of Chemistry at the High School level.
At standard temperature and pressure (STP), one mole of a gas occupies 22.4 liters. Therefore, to find the number of moles of carbon monoxide, we divide the volume of the gas by the molar volume:
Number of moles = 893 L / 22.4 L/mol = 39.87 mol (approx.)
Once we have the number of moles, we can calculate the mass by multiplying the number of moles by the molar mass of carbon monoxide, which is 28.01 g/mol.
Mass = 39.87 mol × 28.01 g/mol = 1116.69 g (approx)
Therefore, a container with a volume of 893 L of carbon monoxide at STP would contain approximately 1116.69 grams of the gas.