Final answer:
There are 0.80592 moles of hydrogen in 876 mL of 0.92 M nitric acid, as each molecule of HNO3 contains one atom of hydrogen.
Step-by-step explanation:
The question asks about calculating the number of moles of hydrogen (H) in a given volume and molarity of nitric acid (HNO3). To find the moles of HNO3 in 876 mL of 0.92 M solution, first convert the volume to liters (876 mL = 0.876 L) and use the molarity to calculate moles of HNO3:
Moles of HNO3 = Molarity (M) × Volume (L) = 0.92 mol/L × 0.876 L = 0.80592 mol HNO3
Since each molecule of HNO3 contains one atom of hydrogen, the moles of hydrogen will be equal to the moles of HNO3:
Moles of H = Moles of HNO3 = 0.80592 mol