Final answer:
To calculate the rise in temperature for a 25 g aluminum block absorbing 10 kJ of heat, the specific heat formula Q = m * c * ΔT is used. The aluminum block's temperature would rise by about 444.44°C when it absorbs the heat based on its specific heat capacity of 900 J/kg°C.
Step-by-step explanation:
The question is asking to calculate the rise in temperature of a 25 g aluminum block when it absorbs 10 kJ of heat. To solve this, we need to use the formula for heat transfer Q = m * c * ΔT, where Q is the heat absorbed, m is the mass, c is the specific heat capacity of aluminum, and ΔT is the change in temperature. The specific heat capacity of aluminum is given as 900 J/kg°C in exercise 40. However, we need to convert the mass of the aluminum from grams to kilograms to match the units of specific heat capacity.
First, convert the mass from grams to kilograms: 25 g = 0.025 kg. Now we have Q = 10,000 J (since 10 kJ = 10,000 J), m = 0.025 kg, and c = 900 J/kg°C. We can rearrange the formula to solve for ΔT: ΔT = Q / (m * c)
ΔT = 10,000 J / (0.025 kg * 900 J/kg°C) = 444.44°C
Thus, the aluminum block would experience a temperature rise of approximately 444.44°C when it absorbs 10 kJ of heat.