Final answer:
The amount of heat required to melt 44.0925 lbs. of ice at 0°C is 200 kJ, including the heat needed to bring the ice to 0°C and the heat needed to bring the water from 0°C to 37°C.
Step-by-step explanation:
In order to calculate the amount of heat required to melt 44.0925 lbs. of ice at 0°C, we need to consider the various stages of the process.
First, we need to bring the ice from -5.0°C to 0.0°C. This requires 4.1 kJ of heat.
Next, we need to melt the ice at 0.0°C. The heat required for this step is 133.6 kJ.
Finally, we need to bring the resulting water from 0.0°C to 37°C, which requires 61.9 kJ of heat.
Adding up these three amounts, we get a total of 200 kJ of heat required to melt the ice.
By calculating the specific heat capacities and heat of fusion, we can determine the total amount of heat needed for this process.