Question

A force f = fx i + fy j acts on a particle that undergoes a displacement of s = sx i + sy j where fx = 7 n, fy = -1 n, sx = 6 m, and sy = 3 m. Find the work done by the force on the particle in units of J.

Answer 1

To calculate the work done by the force, the dot product of the force vector and the displacement vector was computed, resulting in 39 Joules of work.

Step-by-step explanation:

To find the work done by a force on a particle, we use the dot product of the force vector and the displacement vector. For a force f represented by 7 N in the x-direction and -1 N in the y-direction, and displacement s with 6 m in the x-direction and 3 m in the y-direction, the work W is calculated as follows:

W = fx * sx + fy * sy

W = (7 N) * (6 m) + (-1 N) * (3 m)

W = 42 Nm - 3 Nm

W = 39 Nm or 39 Joules (since 1 Nm = 1 J).