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A football is kicked upward from ground level with an initial velocity of 32 feet per second. Its path is represented by the equation , where t is measured in seconds. How long does it take the football to return to the ground?

User Bcarroll
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Final answer:

The time a football kicked upward with a given initial velocity takes to return to the ground is calculated using kinematic equations. Without the complete equation in the question, we can't provide a numeric answer, but general steps are given for solving such problems involving projectile motion.

Step-by-step explanation:

The question asks how long it takes for a football to return to the ground after being kicked upward from ground level with an initial velocity of 32 feet per second. To solve this, we use the kinematic equations for projectile motion. These equations can predict the time in the air, the maximum height, and other aspects of the trajectory of a projectile. However, the equation for the trajectory is missing from the question, so we are unable to provide a numerical answer. Instead, we provide general guidance on how to approach the problem.

To find the time it takes for the football to return to the ground, we need to use the following kinematic equation of motion, where t represents time, v is the initial vertical velocity, g is the acceleration due to gravity, and s is the displacement:

s = vt + ½(-g)t2

Since the final position s (displacement) is 0 (it returns to ground level), we would solve for t when s=0. Since gravity g is approximately 32 ft/s2 and the initial vertical velocity v is 32 ft/s, we would set the equation as:

0 = 32t - ½(32)t2

This quadratic equation can be simplified to find the value of t, representing the time the football remains in the air.

User LuizEduardoMPF
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