Final answer:
To test the claim that the mean of all wait times is more than 30 minutes, perform a one-sample t-test using the given data and a significance level of 0.01. Compare the test statistic to the critical value from a t-table or calculator to make a decision about the null hypothesis.
Step-by-step explanation:
In order to test the claim that the mean of all wait times is more than 30 minutes, we can use a hypothesis test. Let's perform a one-sample t-test using the given data.
- Null hypothesis (H0): The mean wait time is 30 minutes.
- Alternative hypothesis (Ha): The mean wait time is greater than 30 minutes.
- Significance level (α): 0.01
- Test statistic: t = (sample mean - population mean) / (sample standard deviation / sqrt(sample size))
- Compute the test statistic using the given values: t = (sample mean - 30) / (3.5 / sqrt(25)) = (sample mean - 30) / 0.7
- Find the critical value for a one-tailed test with α = 0.01 and degrees of freedom (df) = sample size - 1 = 24. You can use a t-table or a t-distribution calculator to find this critical value.
- Compare the test statistic to the critical value. If the test statistic is greater than the critical value, reject the null hypothesis. Otherwise, fail to reject the null hypothesis.