Question

A 649 ml NaCl solution is diluted to a volume of 1.27 L and a concentration of 8.00 M. What was the initial concentration C1?

Answer 1

The initial concentration C1 of the NaCl solution is approximately 15.61 M.

Step-by-step explanation:

To find the initial concentration, we can use the equation:

C1V1 = C2V2

Where C1 is the initial concentration, V1 is the initial volume, C2 is the final concentration, and V2 is the final volume.

Plugging in the given values, we get:

C1 * 649 mL = 8.00 M * 1.27 L

Simplifying the equation, we find the initial concentration:

C1 = (8.00 M * 1.27 L) / 649 mL

Calculating this, the initial concentration C1 is approximately 15.61 M.