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Given the function h(x) = x² - 6x + 4, determine the average rate of change of the function over the interval -2 ≤ x ≤ 5.

User MaGu
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Final answer:

The average rate of change of the function h(x) = x² - 6x + 4 over the interval -2 ≤ x ≤ 5 is calculated using the endpoints of the interval. Substituting -2 and 5 into the function and then calculating the change in h(x) over the change in x, we find that the average rate of change is -3.

Step-by-step explanation:

To determine the average rate of change of the function h(x) = x² - 6x + 4 over the interval -2 ≤ x ≤ 5, we use the formula:

average rate of change = ∆h / ∆x = (h(x2) - h(x1)) / (x2 - x1)

where (x1, h(x1)) and (x2, h(x2)) are the points on the interval's endpoints. For our function:

  • h(-2) = (-2)² - 6(-2) + 4 = 4 + 12 + 4 = 20
  • h(5) = 5² - 6(5) + 4 = 25 - 30 + 4 = -1

Now, we calculate the average rate of change:

average rate of change = (h(5) - h(-2)) / (5 - (-2)) = (-1 - 20) / (5 + 2) = -21 / 7 = -3

The average rate of change of the function h(x) over the interval from -2 to 5 is -3.

User Fooser
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