Final answer:
To find the volume of 69.6 g of N₂ gas at STP, convert the mass to moles using the molar mass of N₂, then multiply by the molar volume of gas at STP. The calculation shows that at STP, 69.6 g of N₂ occupies approximately 55.68 liters.
Step-by-step explanation:
The volume of 69.6 g of N₂ gas at STP (Standard Temperature and Pressure) can be calculated using the concept of molar volume. At STP, one mole of any ideal gas occupies 22.4 liters. To find the volume that 69.6 g of nitrogen gas occupies at STP, we first need to determine how many moles of N₂ that mass represents. The molar mass of N₂ is 28.0 g/mol, so 69.6 g of N₂ is equivalent to 69.6 g ÷ 28.0 g/mol = 2.4857 mol.
Next, we multiply the number of moles by the molar volume to find the volume at STP:
V = 2.4857 mol × 22.4 L/mol = 55.68 L.
Therefore, the volume of 69.6 g of N₂ gas at STP is approximately 55.68 liters.