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Given the equation of a line: -x + 6y = 12, answer the following questions.

1. Rewrite the equation of this line to slope-intercept form.
2. What is the slope of this line?
3. Write the equation of the line parallel to this line passing through the point (6, 10)?

User Jvargas
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1 Answer

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Final answer:

The given line equation is rewritten into slope-intercept form as y = (1/6)x + 2. The slope of the line is 1/6. The equation of a parallel line passing through (6, 10) starts with y - 10 = (1/6)(x - 6) before simplifying.

Step-by-step explanation:

To rewrite the equation of the line -x + 6y = 12 into slope-intercept form (y = mx + b), we first need to isolate y on one side. Adding x to both sides gives us 6y = x + 12. Then, we divide each term by 6 to solve for y: y = (1/6)x + 2. This is the slope-intercept form of the equation, where m is the slope and b is the y-intercept.

The slope of the line is the coefficient of x in the slope-intercept form, which is 1/6 in our case.

To write the equation of a line parallel to the given line passing through the point (6, 10), we use the same slope of 1/6 since parallel lines have equal slopes. Using the point-slope form y - y1 = m(x - x1), we plug in the point (6, 10) and the slope 1/6 to get: y - 10 = (1/6)(x - 6). Simplifying this will give the equation in slope-intercept form.

User Tobi Oetiker
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