Final answer:
The 10.0-kg box will not move when a 60.0 N force is applied because this force is less than the maximum static frictional force of 73.5 N that it can resist.
Step-by-step explanation:
The student has asked what happens to a 10.0-kg box at rest on a concrete floor when a force of 60.0 N is applied, given the coefficient of static friction is 0.75 and the coefficient of kinetic friction is 0.62.
Firstly, we calculate the maximum static frictional force that needs to be overcome to move the box: fs(max) = μs * N. The normal force (N) is equal to the weight of the box, which is 10.0 kg * 9.8 m/s² = 98 N. So the maximum static frictional force is 0.75 * 98 N = 73.5 N.
Since the applied force (60.0 N) is less than the maximum static frictional force (73.5 N), the box will not move and remain at rest. The static frictional force will be equal to the applied force, resisting the movement up to its maximum value.