Question

500ml of copper (il) sulfate needs to be prepared with a strength of 0.20 moll. What mass of copper (i) sulfate must be used to prepare this solution?

Answer 1

To prepare a 0.20 M solution of copper (II) sulfate in 500 ml of water, 15.962 g of CuSO4 is required.

Step-by-step explanation:

To determine the mass of copper (II) sulfate needed to prepare a solution with a strength of 0.20 mol/L (molar), we first need to calculate how many moles of CuSO4 are required for 500 ml (0.500 L) of solution. To calculate the number of moles needed, we use the formula:

Moles = Molarity × Volume (in liters)

Therefore, 0.20 mol/L × 0.500 L = 0.10 mol of CuSO4. Next, we find the molar mass of CuSO4, which is 159.62 g/mol. To find the mass needed, we multiply the moles required by the molar mass:

Mass = Moles × Molar Mass

So, 0.10 mol × 159.62 g/mol = 15.962 g of CuSO4.

Therefore, to prepare 500 ml of a 0.20 mol/L solution of copper (II) sulfate, 15.962 g of CuSO4 is needed.