Question

Assume the following register contents: t0 = 0xaaaaaaaa, t1 = 0x12345678. For the register values shown above, what is the value of t2 for the following sequence of instructions? sll t2, t0, 44 or t2, t2, t1

Answer 1

The value of t2 for the given sequence of instructions and register contents is 0xaa12345678.

Step-by-step explanation:

To find the value of t2 for the given sequence of instructions, let's break it down step by step:

Step 1:

sll t2, t0, 44

This instruction shifts the value in register t0 to the left by 44 bits and stores the result in t2.

Since t0 contains the hexadecimal value 0xaaaaaaaa, shifting it to the left by 44 bits would result in a value of 0xaa00000000000000.

Step 2:

t2, t2, t1

This instruction performs an OR operation between the values in registers t2 and t1, and stores the result in t2.

Since t2 currently contains the value 0xaa00000000000000 and t1 contains the hexadecimal value 0x12345678, performing an OR operation between them would result in a value of 0xaa12345678.

Therefore, the final value of t2 for the given sequence of instructions and register contents is 0xaa12345678.