Final answer:
The standardized score (Z-score) of 2.60 suggests a value well above the mean. Typically, additional information such as the mean and standard deviation of the population's ages is needed to convert a Z-score to a percentage. However, an approximate correspondence to the 99th percentile suggests Florida has a high percentage of residents over 65 relative to other data points.
Step-by-step explanation:
The standardized score, or Z-score, for Florida being 2.60 indicates that the value is 2.60 standard deviations above the mean. To find the percent of the state's residents that were 65 or older from this standardized score, we need to use a Z-score table or statistical software. However, the question does not provide enough information to make a direct calculation. Typically, one would also need the mean and standard deviation of the population's ages to convert the Z-score into a percentage.
Though, if we consider the standardized score as analogous to percentile ranks, a Z-score of 2.60 roughly corresponds to the 99th percentile. This means that approximately 99 percent of the data values are below this score. Applying this to the demographic information, if 2.60 were the Z-score for the percentage of residents aged 65 or older, it would suggest that this demographic is higher than approximately 99 percent of other percentages in the data set. This implies a very high percentage of the population is 65 or older, but without more data, an exact percentage cannot be calculated.