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The reaction of 176.34 grams of sodium with excess sulfuric acid produced 492.76 grams of sodium sulfate. What is the percent yield of sodium sulfate?

User Scaraux
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Final answer:

To calculate the percent yield of sodium sulfate, divide the actual yield of 492.76 grams by the theoretical yield and multiply by 100. The theoretical yield needs to be calculated based on the moles of sodium and the stoichiometry of the reaction.

Step-by-step explanation:

The percent yield of sodium sulfate can be calculated using the actual yield and the theoretical yield of the product. First, we need to determine the theoretical yield. The balanced chemical equation for the reaction of sodium with sulfuric acid is 2Na + H2SO4 → Na2SO4 + H2. To find the theoretical yield, we can calculate the moles of sodium (assuming 100% reaction efficiency) and use stoichiometry to find the moles of sodium sulfate that would be produced. This can then be converted to grams.

After determining the theoretical yield, the percent yield is found by dividing the actual yield by the theoretical yield, and then multiplying by 100. In this case, the actual yield is 492.76 grams of sodium sulfate. Percent yield is therefore calculated as (actual yield/theoretical yield) x 100%.

Without the molecular weight of sodium and sodium sulfate or additional details, the exact theoretical yield cannot be provided. However, assuming one has the theoretical yield, if it were, for example, 500 grams, then the percent yield would be (492.76 g / 500 g) x 100%, which equals 98.55%.

User Seoul
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