Final answer:
The energy of a photon with a frequency of 19.67×10¹⁷ Hz is calculated using the formula E = hf, where 'h' is Planck's constant and 'f' is the frequency. The energy is found to be 1.303 × 10⁻¹⁶ joules.
Step-by-step explanation:
To calculate the energy of a photon with a frequency of 19.67×10¹⁷ Hz, you can use the formula E = hf, where E is the energy of the photon, h is Planck's constant, and f is the frequency of the photon. Planck's constant (h) is 6.626 × 10⁻³⁴ J·s.
By plugging in the values, you get:
E = (6.626 × 10⁻³⁴ J·s) × (19.67×10¹⁷ Hz)
Performing the multiplication yields:
E = 1.303 × 10⁻¹⁶ J
Thus, the energy of a photon with a frequency of 19.67×10¹⁷ Hz is 1.303 × 10⁻¹⁶ joules.