Final answer:
To find the mass of CaCl₂ produced from 0.621 g of HCl, first calculate the moles of HCl. Then, use the balanced chemical equation to determine the moles of CaCl₂ produced. Finally, convert the moles of CaCl₂ to grams using its molar mass. The mass of CaCl₂ produced is 0.9448 g.
Step-by-step explanation:
To find the mass of CaCl₂ produced from 0.621 g of HCl, we first need to find the moles of HCl using its molar mass. From the balanced chemical equation, we can see that the ratio between HCl and CaCl₂ is 2:1. Therefore, the moles of CaCl₂ produced will be half of the moles of HCl. Finally, we can convert the moles of CaCl₂ to grams using its molar mass.
Step 1: Calculate moles of HCl using its molar mass. Molar mass of HCl = 1 g/mol (H) + 35.45 g/mol (Cl) = 36.45 g/mol. Moles of HCl = Mass of HCl / Molar mass of HCl = 0.621 g / 36.45 g/mol = 0.0170 mol HCl.
Step 2: Since the ratio between HCl and CaCl₂ is 2:1, the moles of CaCl₂ produced will be half of the moles of HCl. Moles of CaCl₂ = 0.0170 mol HCl / 2 = 0.0085 mol CaCl₂.
Step 3: Convert the moles of CaCl₂ to grams using its molar mass. Molar mass of CaCl₂ = 40.08 g/mol (Ca) + 2(35.45 g/mol) (Cl) = 110.98 g/mol. Mass of CaCl₂ = Moles of CaCl₂ × Molar mass of CaCl₂ = 0.0085 mol × 110.98 g/mol = 0.9448 g.