Final answer:
The sex cells have an equal amount of DNA to G1 phase kidney cells at the end of meiosis I, when the cells have a haploid number of chromosomes that consist of two sister chromatids each.
Step-by-step explanation:
The amount of DNA in a person's sex cells is equal to the amount of DNA in one of their G1 phase somatic cells at a specific point during meiosis. In the G1 phase, the cells are diploid, containing two sets of chromosomes. During meiosis, DNA replication occurs, and then the cell goes through two rounds of division: meiosis I and meiosis II. In meiosis I, homologous chromosomes separate, and in meiosis II, sister chromatids separate.
After meiosis I, the cell has undergone one division resulting in two cells, each with a haploid number of chromosomes, but each chromosome still consists of two sister chromatids. Therefore, at the end of meiosis I, the DNA content matches that of a G1 phase cell. This means we’re looking for the point at which the cells have only one set of chromosomes, but without having separated the sister chromatids. The answer is (3) At the end of meiosis I.