Question

A student is driving with a speed of 8 m/s. The signal turns green and the student accelerates at a rate of 2 m/s² for 6 seconds. How far does he/she travel after those 6 seconds?

1) 94 m
2) 74 m
3) 104 m
4) 84 m

Answer 1

The student travels a distance of 84 meters after accelerating at 2 m/s² for 6 seconds, starting from an initial speed of 8 m/s.

Step-by-step explanation:

The student initially travels at a speed of 8 m/s and accelerates at a rate of 2 m/s² for 6 seconds. To determine the distance traveled during this time, we can use the equation of motion s = ut + ½at², where s is the distance, u is the initial velocity, a is the acceleration, and t is the time. Substituting in the given values:

• Initial velocity (u) = 8 m/s
• Acceleration (a) = 2 m/s²
• Time (t) = 6 s

s = (8 m/s)(6 s) + ½(2 m/s²)(6 s)²

s = 48 m + ½(2)(36)

s = 48 m + 36 m

s = 84 m

Therefore, after 6 seconds, the student travels a distance of 84 m.