Question

A solution contains 0.270 m (CH₃)2NH₂I and 0.106 m dimethylamine, (CH₃)2NH. What is the concentration of (CH₃)2NH in the solution?

Answer 1

To find the concentration of (CH₃)₂NH in the solution, calculate the moles of (CH₃)₂NH and divide by the total volume of the solution.

Step-by-step explanation:

To find the concentration of (CH₃)₂NH in the solution, we need to consider the moles of (CH₃)₂NH. Using the given molarity of (CH₃)₂NH of 0.106 m and the volume of the solution, we can calculate the moles of (CH₃)₂NH. Then, we can divide the moles of (CH₃)₂NH by the total volume of the solution to find the concentration.

For example, if the total volume of the solution is 1 liter, and the moles of (CH₃)₂NH is 0.106 moles, then the concentration would be 0.106 M.