Question

A sample of NaOH (molar mass = 40.00 g/mol) with a mass of 1.060 g was added to a solution of HNO₃ in a coffee cup calorimeter for a final volume of 100.0 mL. What is the molarity of the NaOH solution?

Answer 1

The molarity of the NaOH solution is calculated to be 0.265 M by converting 1.060 g NaOH to moles and dividing by the volume of the solution in liters.

Step-by-step explanation:

The molarity of a solution is calculated by dividing the number of moles of the solute by the volume of the solution in liters. To find the molarity of the NaOH solution given a mass of 1.060 g NaOH and a final volume of 100.0 mL, we first convert the mass of NaOH to moles:

1.060 g NaOH × (1 mol NaOH / 40.00 g NaOH) = 0.0265 mol NaOH

Next, we convert the volume of solution to liters:

100.0 mL × (1 L / 1000 mL) = 0.100 L

Finally, we calculate the molarity:

Molarity = moles of solute / liters of solution

Molarity = 0.0265 mol / 0.100 L = 0.265 M NaOH