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A spring is hanging vertically at equiLiBrium. When a mass of 2.2 kg is attached to the spring, the spring stretches by 3.4 cm. What is the spring constant (k) for the spring?

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Final answer:

To find the spring constant, we can use Hooke's Law, which states that the force exerted by a spring is directly proportional to its displacement from equilibrium. In this case, the displacement is 0.034 m (3.4 cm) when a mass of 2.2 kg is attached to the spring. By plugging in the values, we can solve for the spring constant, which is found to be 64.71 N/m.

Step-by-step explanation:

The spring constant (k) represents the stiffness of a spring and is defined as the force required to stretch or compress the spring by a certain distance. To find the spring constant, we can use Hooke's Law, which states that the force exerted by a spring is directly proportional to its displacement from equilibrium:

F = k * x,

where F is the force, k is the spring constant, and x is the displacement from equilibrium. In this case, the displacement is 0.034 m (3.4 cm) when a mass of 2.2 kg is attached to the spring. Plugging in the values, we can solve for the spring constant:

k = F / x = (m * g) / x = (2.2 kg * 9.8 m/s^2) / 0.034 m = 64.71 N/m.

Therefore, the spring constant for this spring is 64.71 N/m.

User Jostein Topland
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