Question

A shell is fired from the ground with an initial speed of 1.67 ✕ 10³ m/s at an initial angle of 57° to the horizontal. What is the initial vertical velocity of the shell?

1) 0 m/s
2) 1.67 ✕ 10³ m/s
3) 1.67 ✕ 10³ m/s * sin(57°)
4) 1.67 ✕ 10³ m/s * cos(57°)

Answer 1

The initial vertical velocity of the shell fired at an angle of 57° is 1.67 × 10³ m/s × sin(57°).

Step-by-step explanation:

The initial vertical velocity of the shell can be found by taking the vertical component of the initial velocity vector. This requires the use of trigonometric functions to break down the initial velocity into horizontal and vertical components. Since the shell is fired at an angle of 57°, the vertical component is found by multiplying the initial speed by the sine of the angle. Therefore, the initial vertical velocity of the shell is 1.67 × 10³ m/s × sin(57°).