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A right circular cylinder made of silver has a radius of 1.77 cm and a length of 13.3 cm. What is the moment of inertia of the cylinder about the axis of symmetry along its length?

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Final answer:

The moment of inertia of a right circular cylinder about its axis of symmetry along its length can be calculated using the formula: I = (1/2) * m * r^2. This formula requires the mass and radius of the cylinder. The mass can be calculated using the density of silver and the volume formula for a cylinder.

Step-by-step explanation:

The moment of inertia of a right circular cylinder about its axis of symmetry along its length can be calculated using the formula:

I = (1/2) * m * r^2

Where I is the moment of inertia, m is the mass of the cylinder, and r is the radius of the cylinder.

In this case, the mass of the cylinder is not given. So, we need the density of silver to calculate the mass. The density of silver is approximately 10.5 grams per cubic centimeter.

Using the formula for volume of a cylinder, V = π * r^2 * h, we can find the mass:

m = density * V = 10.5 g/cm^3 * π * (1.77 cm)^2 * 13.3 cm

Once we have the mass, we can substitute it into the moment of inertia formula:

I = (1/2) * m * r^2

Calculating the values will give you the moment of inertia of the cylinder.

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