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A sample of neon gas at a pressure of 900. torr and a temperature of 22.4°C, occupies a volume of 531 ml. If the gas is compressed at constant temperature until its pressure is 1.09×103 torr, what will be the volume of the gas sample?

User Neemaximo
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Final answer:

Using Boyle's Law, the volume of a neon gas sample is calculated to be 437 ml after it is compressed from 900 torr to 1.09×103 torr at constant temperature. The formula P1 * V1 = P2 * V2 is applied to find the new volume.

Step-by-step explanation:

The question involves the application of Boyle's Law, which states that for a given mass of an ideal gas at constant temperature, the volume of the gas is inversely proportional to its pressure. To solve for the new volume after compression at constant temperature, the initial conditions of pressure (P1) and volume (V1) are related to the final conditions (P2 and V2) using the equation P1 * V1 = P2 * V2.

Initially, we have P1 = 900 torr, V1 = 531 ml, and P2 = 1.09×103 torr. We can solve for V2 by rearranging the equation to V2 = (P1 * V1) / P2. Plugging in the values, V2 = (900 torr * 531 ml) / 1.09×103 torr, which calculates to V2 = 437 ml (rounded to three significant figures).

The final volume of the neon gas after compression will be 437 ml, assuming that temperature remains constant during the compression process.

User Volkan Ceylan
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