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A private jet can fly 1833 miles against a 30-mph headwind in the same amount of time it can fly 2397 miles with a 30-mph tailwind. What is the speed of the jet?

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Final answer:

The speed of the jet is approximately 99.92 mph.

Step-by-step explanation:

To find the speed of the jet, we can use the concept of relative velocity. Let's assume the speed of the jet is 'v' and the speed of the wind is 'w'. When the jet is flying against the headwind, its effective speed will be reduced by the speed of the headwind, so its speed relative to the ground will be 'v - w'. Similarly, when the jet is flying with the tailwind, its effective speed will be increased by the speed of the tailwind, so its speed relative to the ground will be 'v + w'.

We are given that the jet can fly 1833 miles against the headwind in the same time it can fly 2397 miles with the tailwind. This means that:

1833 / (v - 30) = 2397 / (v + 30)

Simplifying this equation, we can cross-multiply:

1833(v + 30) = 2397(v - 30)

Expanding both sides of the equation:

1833v + 54990 = 2397v - 71910

Combining like terms:

56427 = 564v

Dividing both sides by 564:

v = 99.92 mph

Therefore, the speed of the jet is approximately 99.92 mph.

User Johannes Jander
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