Final answer:
The reaction between Pb(NO₃)₂ and K₂CrO₄ forms PbCrO₄(s). The balanced net ionic equation is Pb²⁺(aq) + CrO₄²⁻(aq) → PbCrO₄(s). In this reaction, the lead(II) ion combines with the chromate ion to form lead(II) chromate, which is insoluble in water and precipitates out as a solid.
Step-by-step explanation:
The reaction Pb(NO₃)₂(aq) + K₂CrO₄(aq) forms PbCrO₄(s) + 2KNO₃(aq). The balanced net ionic equation can be written as Pb²⁺(aq) + CrO₄²⁻(aq) → PbCrO₄(s). In this reaction, the lead(II) ion combines with the chromate ion to form lead(II) chromate, which is insoluble in water and precipitates out as a solid.
reaction between Pb(NO₃)₂ and K₂CrO₄ forms PbCrO₄(s). The balanced net ionic equation is Pb²⁺(aq) + CrO₄²⁻(aq) → PbCrO₄(s). In this reaction, the lead(II) ion combines with the chromate ion to form lead(II) chromate, which is insoluble in water and precipitates out as a solid.