Question

Gaseous ammonia chemically reacts with oxygen (O₂) gas to produce nitrogen monoxide gas and water vapor. Calculate the moles of water produced by the reaction of 1.9 mol of ammonia. Be sure your answer has a unit symbol, if necessary, and round it to the correct number of significant digits.

Answer 1

The reaction of 1.9 mol of gaseous ammonia with oxygen produces 2.85 mol of water vapor. The calculation is based on the stoichiometric relationship between ammonia and water in the balanced chemical equation.

Step-by-step explanation:

The reaction involving gaseous ammonia and oxygen gas to produce nitrogen monoxide gas and water vapor is represented by the balanced chemical equation:

4NH3(g) + 5O2(g) → 4NO(g) + 6H2O(l)

To calculate the moles of water produced from the reaction of 1.9 mol of ammonia, we use a stoichiometric ratio from the balanced equation. According to the equation, 4 moles of NH3 produce 6 moles of H2O, so the ratio of NH3 to H2O is 4:6 or 2:3. By setting up the stoichiometric calculation like this:

1.9 mol NH3 × (6 mol H2O / 4 mol NH3) = 2.85 mol H2O

Therefore, the reaction of 1.9 mol of ammonia produces 2.85 mol of water vapor. This result is rounded to three significant digits to match the number of significant digits in the given amount of ammonia.