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Find f. f ³(t) = 3/(t)¹/² , f(4) = 17, f ²(4) = 4

User Illayda
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1 Answer

5 votes

Answer:

The function f(x) is f(x) = 4/5x^(7/2) + (17 - 4/5 * 4^(7/2)).

Explanation:

Given the information provided, we can determine the function f(x) using the given constraints:

f³(t) = 3/(t)^(1/2)

f(4) = 17

f²(4) = 4

To solve for f(x), let's start by integrating the first equation three times:

f''(t) = 3 ∫ (t)^(1/2) dt = 3t^(3/2) + C1

f'(t) = 3 ∫ (t)^(3/2) dt = 2t^(5/2) + C2

f(t) = 4/5t^(7/2) + C3

Now, let's use the given values of f(4) = 17 and f²(4) = 4 to solve for the constants C1, C2, and C3.

Substituting t = 4 into the expression for f(t), we get:

f(4) = 4/5 * 4^(7/2) + C3 = 17

Solving for C3, we get:

C3 = 17 - 4/5 * 4^(7/2)

Substituting t = 4 into the expression for f'(t), we get:

f'(4) = 2 * 4^(5/2) + C2 = 4 * 2^(5/2)

Solving for C2, we get:

C2 = 4 * 2^(5/2) - 2 * 4^(5/2) = 0

Therefore, the function f(x) is f(x) = 4/5x^(7/2) + (17 - 4/5 * 4^(7/2))

User Thomas Kaliakos
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