134k views
4 votes
Find the equation of a line that contains the points (4,-8) and (-5,1). Write the equation in slope-intercept form.

1 Answer

4 votes

Final answer:

The equation of a line containing the points (4,-8) and (-5,1) is found by calculating the slope and using it with one of the points to determine the y-intercept. The result in slope-intercept form is y = -x - 4.

Step-by-step explanation:

To find the equation of a line in slope-intercept form that contains the points (4,-8) and (-5,1), we first need to calculate the slope (m). The slope formula is (y2 - y1) / (x2 - x1), where (x1, y1) and (x2, y2) are the points on the line. So for our points, the slope m is (1 - (-8)) / (-5 - 4) = 9 / -9 = -1.

Next, we use one of the points and the slope to find the y-intercept (b) of the line. We can use the point-slope form: y - y1 = m(x - x1) and plug in m = -1 and the coordinates (4, -8): y - (-8) = -1(x - 4). Simplify to get the slope-intercept form: y = -1x + 4 - 8, which simplifies further to y = -x - 4.

Therefore, the equation of the line in slope-intercept form is y = -x - 4.

User Otto Fajardo
by
8.9k points

No related questions found

Welcome to QAmmunity.org, where you can ask questions and receive answers from other members of our community.

9.4m questions

12.2m answers

Categories