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Find the margin of error for the given values of c, σ, and n. c=0.95, σ=2.8, n=64?

User PeterD
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Final answer:

The margin of error for c=0.95, σ=2.8, and n=64 is calculated using the Z-score for a 95% confidence interval, which results in a margin of error of 0.686.

Step-by-step explanation:

To find the margin of error for the given values, we need to use the Z-score associated with a 95% confidence level (c=0.95). Typically, for a 95% confidence interval, the Z-score for a two-tailed test is approximately 1.96. The formula for the margin of error (E) when the population standard deviation (σ) is known is E = Z * (σ / √n), where Z is the Z-score, σ is the population standard deviation, and n is the sample size.

Substituting the given values into the formula, we have:

  • Z = 1.96
  • σ = 2.8
  • n = 64

Now, we calculate the margin of error:

E = 1.96 * (2.8 / √64)

= 1.96 * (2.8 / 8)

= 1.96 * 0.35

= 0.686

So, the margin of error is 0.686.

User TheGeekNess
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