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Evaluate 25/sqrt(x²-1) as x approaches negative infinity?

User PRR
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Final answer:

When evaluating 25/sqrt(x²-1) as x approaches negative infinity, the denominator becomes very large, resulting in the expression approaching 0.

Step-by-step explanation:

To evaluate 25/sqrt(x²-1) as x approaches negative infinity, we need to look at the behavior of the function as x becomes a very large negative number. Since x² grows faster than x, as x becomes more negative, becomes very large, making the square root of (x²-1) almost equal to the square root of x², which is |x|. So, our expression simplifies to 25/|x| as x approaches negative infinity.

Since we are dealing with negative infinity, |x| will be a very large positive number. Therefore, 25/|x| will approach zero. Thus, the value of the original expression as x approaches negative infinity is 0.

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