Question

A laser diode requires 3.2v across it to make it work. This means that its photons will have an energy of 3.2ev. Calculate the wavelength of the light emitted.

Answer 1

The wavelength of the light emitted by a laser diode with 3.2eV energy is approximately 638 nm.

Step-by-step explanation:

The wavelength of light emitted by a laser diode can be found using the formula:

Wavelength = (Speed of Light) / (Frequency)

Since we know the energy of the photons emitted by the laser diode is 3.2eV, we can use the equation:

Energy = Planck's Constant * Frequency

Combining these two equations, we can rearrange to solve for the wavelength:

Wavelength = (Speed of Light) / [(Planck's Constant * Energy)]

Plugging in the values, we get:

Wavelength = (3.00 x 10^8 m/s) / [(6.63 x 10^-34 J s) * (3.2 eV * 1.6 x 10^-19 J/eV)]

Calculating this, we find that the wavelength of the light emitted by the laser diode is approximately 638 nm.