Final answer:
The thermochemical equation for the reaction of one mole of sucrose with potassium chlorate includes the reactants and products, with a heat term (ΔH) that represents the heat released during the reaction. The exact value of ΔH needs to be calculated or provided to complete the equation.
Step-by-step explanation:
The thermochemical equation for the reaction of one mole of sucrose with potassium chlorate, which yields carbon dioxide, water, and potassium chloride can be written as follows:
To complete this equation, we need to know the amount of heat released or absorbed during the reaction. Since 43.7 kJ of heat are produced when 2.67 g of sucrose reacts with 7.19 g of potassium chlorate, we can assume that for the reaction of one mole of sucrose the heat evolved will be proportional. Based on the molecular weight of sucrose (342.30 g/mol), the heat released for one mole of sucrose can be calculated using stoichiometry and included in the thermochemical equation. However, to provide a complete answer, the exact molar enthalpy change (ΔH) must be known or given.