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What is the area of a parallelogram formed by vectors A = <2, 6> and B = <3, 1>?

1) 2 square units
2) 6 square units
3) 16 square units
4) 20 square units

1 Answer

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Final answer:

The area of a parallelogram formed by vectors A = <2, 6> and B = <3, 1> is 16 square units.

Step-by-step explanation:

The area of a parallelogram formed by vectors A = <2, 6> and B = <3, 1> can be calculated using the cross product of the two vectors. The cross product A x B gives a vector whose magnitude is equal to the area of the parallelogram formed by vectors A and B. The formula for the cross product in two dimensions is |A x B| = |A||B|sin(θ), where θ is the angle between the two vectors.

To find the area without knowing the angle, we can take the determinant of the matrix formed by placing vector A's components in the first row and vector B's components in the second row:

|A x B| = |2 * 1 - 6 * 3| = |-16| = 16 square units.

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