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What is the value of kb for the conjugate base of HCN (Ka = 4.9 × 10⁻¹⁰)?

User Rajahsekar
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Final answer:

The Kb value for the conjugate base of HCN is 2.04 × 10⁻µ when Ka for HCN is 4.9 × 10⁻¹⁰ and the Kw of water is 1.0 × 10⁻¹⁴.

Step-by-step explanation:

The value of Kb for the conjugate base of HCN, given that the Ka for HCN is 4.9 × 10⁻¹⁰, can be calculated using the relation Ka × Kb = Kw, where Kw is the ionization constant of water. At 25 °C, Kw is equal to 1.0 × 10⁻¹⁴. Therefore, the Kb for the conjugate base of HCN is determined by rearranging the expression as Kb = Kw / Ka.

Using the given values: Kb = (1.0 × 10⁻¹⁴) / (4.9 × 10⁻¹⁰)

Kb = 2.04 × 10⁻µ for the conjugate base of HCN.

User Artanis
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