Question

During a six second time interval constant force is exerted on a 250 kg scooter if the scooter increases its velocity from 6 m/s to 28 m/s then what is the magnitude of the force exerted on the scooter?

Answer 1

The force exerted on the scooter is calculated using Newton's second law of motion (F = ma). With an acceleration of 3.67 m/s² over a 6 second interval, the force is determined to be 917.5 N.

Step-by-step explanation:

To calculate the magnitude of the force exerted on the scooter, we can use Newton's second law of motion, which states that force equals mass times acceleration (F = ma). First, we need to find the scooter's acceleration during the time interval. Acceleration is defined as the change in velocity divided by the time taken for that change (a = (v - u) / t), where 'v' is the final velocity, 'u' is the initial velocity, and 't' is the time taken.

The change in velocity (v - u) for the scooter is 28 m/s - 6 m/s = 22 m/s. The time interval during which this change occurred is 6 seconds. Thus, the acceleration is:
a = (v - u) / t = 22 m/s / 6 s = 3.67 m/s2.

Now that we have the acceleration, we can calculate the force exerted on the 250 kg scooter using F = ma:

F = 250 kg * 3.67 m/s2 = 917.5 N

The magnitude of the force exerted on the scooter is therefore 917.5 Newtons (N).