Final answer:
To determine the amount of heat transfer in an isothermal heat rejection process of a Carnot cycle, you can use the equation Q = T · ΔS where Q is the heat transfer, T is the temperature in Kelvin, and ΔS is the change in entropy. By substituting the given values, we find that the amount of heat transfer in btu is -224.85 btu.
Step-by-step explanation:
In an isothermal heat rejection process, the working fluid of a Carnot cycle experiences a change in entropy. In this case, the entropy change is given as -0.730 btu/r. The temperature of the heat sink is 95°F. To determine the amount of heat transfer in btu, we can use the equation: Q = T · ΔS. where Q is the heat transfer, T is the temperature in Kelvin, and ΔS is the change in entropy. First, we need to convert the temperature from Fahrenheit to Kelvin: T = (95°F + 459.67) × 5/9 = 308.15 K. Substituting the values into the equation, we get Q = 308.15 K · (-0.730 btu/r) = -224.85 btu. Therefore, the amount of heat transfer in btu is -224.85 btu.