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Consider the concentration cell in which the metal ion has a charge of 4, and the solution concentrations are: dilute solution = 0.021 m concentrated solution = 4.035 m. What is the predicted ecell, using the Nernst equation?

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Final answer:

To calculate the Ecell of a concentration cell, one would use the Nernst equation, inserting the provided concentrations, the standard cell potential, and the partial pressure of Cl2 at standard conditions of 25°C (298 K).

Step-by-step explanation:

To predict the electrochemical cell potential (Ecell) of a concentration cell using the Nernst equation, we need to consider the metal ion with a charge of 4+. In this particular cell, the concentrations are 0.021 M for the dilute solution and 4.035 M for the concentrated solution. It's important to note that the reaction involves the net transfer of two electrons (n = 2) because the metal ion in question changes from a 4+ to a 3+ oxidation state during the reaction.

Assuming standard conditions of 25°C (298 K), we can simplify the Nernst equation to:

Ecell = Ecell° - (RT/nF)ln(Q)

Where Ecell° is the standard cell potential, R is the gas constant, T is temperature in kelvin, n is the number of moles of electrons transferred, F is Faraday's constant, and Q is the reaction quotient. To solve this problem, we would need the standard cell potential and the partial pressure of Cl2, which are not provided. Once we have these values, we insert them into the Nernst equation along with the given concentration values to calculate the Ecell.

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