Final answer:
The visible light with a frequency of 5.347x10ⁱ⁴Hz has a wavelength of 561 nm, an energy of 3.546x10⁻J per photon, and would typically be perceived as yellow-green in color.
Step-by-step explanation:
The question asks to find the wavelength, energy per photon, and color of visible light with a frequency of 5.347x10ⁱ⁴Hz. To calculate the wavelength (λ), we use the equation c = λ×f, where 'c' is the speed of light in a vacuum (approximately 3.00x10¸m/s) and 'f' is the frequency. Using the given frequency, the wavelength is λ = c / f = 3.00x10¸m/s / 5.347x10ⁱ⁴Hz ≈ 561 nm.
Next, to find the energy of a photon (E), we use the equation E = h×f, where 'h' is Planck's constant (6.626x10⁻³⁴Js). Thus, E = 6.626x10⁻³⁴Js × 5.347x10ⁱ⁴Hz ≈ 3.546x10⁻J per photon.
The color of the light can be inferred from its wavelength. In the visible spectrum, a wavelength of 561 nm typically corresponds to a yellow-green color. Therefore, the given light would appear yellow-green to the human eye.