The moment of inertia of a rod about its pivot point is equal to (1/48) * m * l², where m is the mass of the rod and l is the total length of the rod.
The moment of inertia of a rod about its pivot point depends on its distribution of mass. In this case, the rod is pivoted at its center. The moment of inertia of the rod about its pivot point can be calculated using the formula: I = (1/12) * mr², where I is the moment of inertia, m is the mass of the rod, and r is the length of the rod.
Since the rod is pivoted at its center, the distance from each point on the rod to the pivot point is equal to half of the total length of the rod. Substituting this value of r into the formula gives: I = (1/12) * m * (l/2)². Simplifying further, we get: I = (1/12) * m * l² / 4, which is equal to (1/48) * m * l².
Therefore, the moment of inertia of the rod about its pivot point is (1/48) * m * l².