Question

Consider a 18-loop coil with a diameter of 6 cm; a north-leading bar magnet moves further away from the coil (where the bar magnet is perpendicular to the cross section of the coil, and the north pole is closest to the coil as the magnet moves away). The magnetic field value changes from 0.15 T to 0.00025 T in 2.2 s. What is the rate of change of magnetic field?

1) 0.068 T/s
2) 0.068 mT/s
3) 0.068 Gs/s
4) 0.068 kT/s

Answer 1

The rate of change of the magnetic field is 0.068 T/s, which is calculated by the difference in magnetic field values divided by the time over which the change occurs.

Step-by-step explanation:

The rate of change of the magnetic field is calculated by taking the difference in magnetic field values and dividing by the time interval over which the change occurs. In this scenario, the magnetic field changes from 0.15 T to 0.00025 T in 2.2 seconds. Thus, the rate of change of the magnetic field (dB/dt) is given by:

(0.15 T - 0.00025 T) / 2.2 s = 0.14975 T / 2.2 s = 0.068 T/s.

This implies that the correct answer is option 1) 0.068 T/s.