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Consider the circuit below. The battery has an emf of ε=30.00V and an internal resistance of r=1.00Ω. (a) Find the equivalent resistance of the circuit and the current out of the battery. (b) Find the current through each resistor. (c) Find the potential drop across each resistor. (d) Find the power dissipated by each resistor. (e) Find the total power supplied by the batteries.

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Final answer:

The student's physics question involves conducting a series circuit analysis to find equivalent resistance, current, voltage drop, power dissipation and total power from a battery.

Step-by-step explanation:

The student's question involves calculating various electrical properties of a circuit containing a battery and resistors in series. Circuit analysis is key here and includes finding the equivalent resistance, current through the battery and each resistor, potential drop across each resistor, power dissipated by each resistor, and the total power supplied by the battery.

Equivalent Resistance and Current

To calculate the equivalent resistance, one should sum up all the resistances in the circuit since they are in series, then add the internal resistance of the battery. Using Ohm's Law (V = IR), the current out of the battery can be calculated.

Voltage Drop and Power Dissipation

The potential drop across each resistor in a series circuit is found by multiplying the current by each resistor's resistance. Power dissipation in each resistor is given by P=I2R. For total power supplied by the battery, use P=IV, where V is the emf of the battery.

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