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In the reaction MgCl₂ + 2KOH → Mg(OH)₂ + 2kci, how many moles of Mg(OH)₂ are produced for every mole of MgCl₂?

User MiniMe
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Final answer:

For each mole of MgCl₂ that reacts, one mole of Mg(OH)₂ is produced according to the balanced chemical equation.

Step-by-step explanation:

In the reaction MgCl₂ + 2KOH → Mg(OH)₂ + 2KCl, the stoichiometric coefficients indicate the mole ratio of the reactants to the products. According to this balanced chemical equation, one mole of magnesium chloride (MgCl₂) reacts with two moles of potassium hydroxide (KOH) to produce one mole of magnesium hydroxide (Mg(OH)₂) and two moles of potassium chloride (KCl). Therefore, for every mole of MgCl₂ that reacts, one mole of Mg(OH)₂ is produced.

User Samantha Blasbalg
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