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In this equation N₂ + 3H₂ → 2NH₃, if given 4 moles of N₂, what volume of NH₃ will be produced at STP?

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Final answer:

According to the balanced equation, 8 moles of NH₃ will be produced when given 4 moles of N₂ at STP. This corresponds to a volume of 179.2 liters of NH₃.

Step-by-step explanation:

According to the balanced chemical equation N₂ + 3H₂ → 2NH₃, the mole ratio between N₂ and NH₃ is 1:2. This means that for every 1 mole of N₂, 2 moles of NH₃ are produced. Given that we have 4 moles of N₂, we can use this ratio to determine the moles of NH₃ produced. 4 moles of N₂ x 2 moles of NH₃/1 mole of N₂ = 8 moles of NH₃.

At STP (Standard Temperature and Pressure), 1 mole of any ideal gas occupies 22.4 liters. So, 8 moles of NH₃ will occupy 8 moles x 22.4 liters/mole = 179.2 liters of NH₃.

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