167k views
5 votes
In the reaction mgcl 2KOH > Mg(OH)₂ 2kci, how many moles of Mg(OH)₂ are produced for every mole of MgCl₂?

User Mina Atia
by
8.6k points

1 Answer

3 votes

Final answer:

In the chemical equation MgCl2 + 2KOH → Mg(OH)2 + 2KCl, one mole of magnesium hydroxide (Mg(OH)2) is produced for every mole of magnesium chloride (MgCl2).

Step-by-step explanation:

The stoichiometry of a chemical reaction tells us the relationship between the quantities of reactants and products in a chemical equation.

When looking at the balanced equation MgCl2 + 2KOH → Mg(OH)2 + 2KCl, we see that for every mole of magnesium chloride (MgCl2), one mole of magnesium hydroxide (Mg(OH)2) is produced. Therefore, the answer is that one mole of Mg(OH)2 is produced for every mole of MgCl2.

User GamerJosh
by
8.5k points