Question

If the pOH of a Ba(OH)₂ solution is 1.88 at 25°C, what is the concentration (in M) of barium hydroxide? Round your answer to four places past the decimal.

Answer 1

The concentration of barium hydroxide in the solution is approximately 0.0316 M.

Step-by-step explanation:

To find the concentration of barium hydroxide (Ba(OH)₂) in the solution, we can use the pOH value. The formula to find the pOH is pOH = -log[OH-]. Since the pOH of the solution is given as 1.88, we can rearrange the formula to find the concentration of hydroxide ions ([OH-]).

First, we take the antilog of the pOH value to find [OH-]. 10^(1.88) ≈ 0.015816. So, the concentration of hydroxide ions is approximately 0.0158 M.

Since barium hydroxide (Ba(OH)₂) is a strong base and completely ionizes in water, the concentration of barium hydroxide is twice the concentration of hydroxide ions. Therefore, the concentration of barium hydroxide is approximately 2 * 0.0158 = 0.0316 M.